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Shift Points, Power, and Gearing

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Old Mar 9, 2006, 06:18 PM
  #31  
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ok, well I guess I dont have my terminology correct, lol.

I am not a scientist nor a physisist (Cant even spell it ).

You can multiply, divide or cut in half whatever TQ, power, whatever is the correct way to write it all you want.

My point was VERY simple.... generally speaking, lower gears make a car accelerate faster.

There is a point when the lower gear ratio will not accelerate the car faster.. the reason why the lower gear will accelerate the car quicker is because the lower gear gets to multiply the TQ more than the higher gear. So even though your motor is making less TQ you can still accelerate faster until the multiplied TQ is lower than the TQ from the next gear. TQ changes in each gear, I am sorry if I said the word power instead of TQ.
Old Mar 9, 2006, 07:38 PM
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Good thread. Free bump.
Old Mar 9, 2006, 08:29 PM
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Maximize net torque for the amt of time = most work done. I learned that in the one phs ix class I had to take
Old Mar 9, 2006, 08:55 PM
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Originally Posted by C6C6CH3vo
Maximize net torque for the amt of time = most work done. I learned that in the one phs ix class I had to take
Yes that is the point exactly here. To figure out the maximum TQ average you need to take the TQ from the transmission output, not the engine TQ. That is what these equations do for ya.
Old Mar 10, 2006, 07:58 AM
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I didn't mean to be so arsy, but I haven't been sleeping lately!

Anyway, the intention of this post is a very good one. Deserves a bump...
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